Determine the average rate of change of B from t = 0s

Determine the average rate of change of B from t = 0s to t =392s.
A⟶2B

Time (s)	Concentration of A (M)
0	0.69
191	0.395
382	0.1

First of all, we need to find the average rate if disappearence for A, where the formula is -ΔC/Δt

First rate (A) = -ΔC/Δt = – (0.430-0.720)/(196-0) = 1.48 * 10^-3 mol/(L*s)

Second rate (A) = -Δc/Δt = – (0.140-0.430)/(392-196) = 1.48 * 10^-3 mol/(L*s)

As we can see, the average rate of A equals 1.48 * 10^-3 mol/(L*s)

Provided that A⟶2B,

The average rate of change (B) = 1.48 * 10^-3 * 2 = 2.96 * 10^-3mol/(L*s)

Chemistry

4 years ago

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