Let t1 be 2s, t2 be 5s
The velocity after 2 seconds is
V=a ∙ t1
V=4∙2=8(m/s)
The final velocity is equal to velocity after 2 seconds, because during last 5 seconds the velocity was constant.
So the answer is:
The final velocity is 8 m/s
Let t1 be 2s, t2 be 5s
The velocity after 2 seconds is
V=a ∙ t1
V=4∙2=8(m/s)
The final velocity is equal to velocity after 2 seconds, because during last 5 seconds the velocity was constant.
So the answer is:
The final velocity is 8 m/s