t[sx)] can be evaluated by replacing x with s(x) in the equation for t(x).
t[s(x)] = 2[s(x)]2 + 2
= 2(-x-1)2 + 2 {Replacing s(x) with -x -1}
So
t[s(3)] = 2(-3-1)2 + 2 {Substitute 3 for x}
= 2(-4)2 + 2
= 34
Or
s(3) = -3 -1 = -4
t[s(3)] = 2[-4]2 + 2
= 34
3 years ago
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